z^2-3z+2/z^2+3z-4-z^2+6z+8/z^2-4=z

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Solution for z^2-3z+2/z^2+3z-4-z^2+6z+8/z^2-4=z equation: 



z^2-3z+2/z^2+3z-4-z^2+6z+8/z^2-4=z

We move all terms to the left:

z^2-3z+2/z^2+3z-4-z^2+6z+8/z^2-4-(z)=0



Domain of the equation: z^2!=0

z^2!=0/

z^2!=√0

z!=0

z∈R



We add all the numbers together, and all the variables

5z+2/z^2+8/z^2-8=0

We multiply all the terms by the denominator


5z*z^2-8*z^2+2+8=0

We add all the numbers together, and all the variables

-8z^2+5z*z^2+10=0

Wy multiply elements

-8z^2+5z^3+10=0

We do not support ezpression: z^3

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